Diagnose the Error Message
- The error message "cannot convert 'void' to 'uint8\_t' in assignment" typically indicates that you're trying to assign a result from a function that returns `void` to a variable of type `uint8_t`. This might happen inadvertently if you're calling a function that performs operations or outputs without a return value and attempting to use its result in an assignment.
- Carefully examine the line of code generating the error. Look for a function call on that line and check its return type in the function's definition or documentation.
Review Function Signatures
- Identify any function calls assigned to a `uint8_t` variable. Verify the return type of these functions. The compiler error suggests that at least one of these functions might have a `void` return type.
- Modify the function return type to `uint8_t` if a return value is necessary, or adjust the code to not use its return value if no return is intended or required.
Modify Function Implementations
Avoid Assigning Void Function Results
- If the function correctly should not return a value, do not attempt to assign its result to a variable. This is a logical error, as C++ does not permit assignment of `void` to other types.
- Replace assignments like `uint8_t value = functionName();` with a direct function call `functionName();` where the function is responsible for side-effects rather than returning results.
Refactor Code for Proper Logic
Use Compiler Output for Guidance
- Compilers generally provide direct information pointing to the location of the error. Utilize this output to navigate directly to the problematic code section, making bedbugging more efficient.
- If additional errors are present after fixing the main problem, continue to adjust and compile iteratively, ensuring that all instances of similar errors are resolved.